1+34y+289y^2=

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Solution for 1+34y+289y^2= equation:


Simplifying
1 + 34y + 289y2 = 0

Solving
1 + 34y + 289y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + 17y)(1 + 17y) = 0

Subproblem 1

Set the factor '(1 + 17y)' equal to zero and attempt to solve: Simplifying 1 + 17y = 0 Solving 1 + 17y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 17y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 17y = 0 + -1 17y = 0 + -1 Combine like terms: 0 + -1 = -1 17y = -1 Divide each side by '17'. y = -0.05882352941 Simplifying y = -0.05882352941

Subproblem 2

Set the factor '(1 + 17y)' equal to zero and attempt to solve: Simplifying 1 + 17y = 0 Solving 1 + 17y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 17y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 17y = 0 + -1 17y = 0 + -1 Combine like terms: 0 + -1 = -1 17y = -1 Divide each side by '17'. y = -0.05882352941 Simplifying y = -0.05882352941

Solution

y = {-0.05882352941, -0.05882352941}

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